| 4x2 – 121 + 5 = 0 ?

4×2-121+5=0

8-121+5=0

-113+5=0

-108=0

Step-by-step explanation:

Here are your Explanations

Step 1

4x2 – 121 + 5 = 0  obsere the questions

Step 2

4x2 – 121 + 5 = 0  Simplify

4x2−116=0

Step 3

4x2−116=0  Add 116 to the sides

4x2=116

Step 4

4x2=116  Divide the sides by 4

x=29  Then you take the square root

Answer : sqrt29 or -sqrt29

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions