If one sound has a relative intensity 1403 times that of another, how do their decibel levels compare? Hint: dB = 10*LOG(intensity)
The more intense sound is decibels greater than the other.

12+3b -1=-5-b -12-1+5=-b-3b -8=-4b

Remember, you can do anything to an equation as long as you do it to both sidesminus 36 from both sides4.5(8-x)=66-2.5(3x+24)distribute36-4.5x=66-7.5x-60add like terms36-4.5x=-7.5x+6add 7.5x to both sides36+3x=6minus 36 from both sides3x=-30divide both sides by 3x=-10