Anumber is made up of two digits whose sum is 9. if this number is now divided into the number made up of the same digits but in reverse order the result is six-fifths. find the number?
step plz

*963.To find the answer, let's:
1.First, let's find all two digit numbers whose sum is 9. They are,{18,27,36,45,54,63,72,81,90}
2.Next let's write each number  with their counterparts in reverse order
{18,81},{27,72},{36,63},{45,54},{90,09}
3.it is said that if the number is divided by itself in reverse order, the result is six-fifths or 6/5,so let's divide the numbers in the curly brackets.
{18/81=2/9, 81/18=9/2},{ 27/72=3/8, 72/27=8/3},{36/63=4/7,63/36=7/4}, {45/54=5/6,54/45=6/5} ,{90/09=10,09/90=1/10}
4.The only number whose two digits add up to 9 and when divided by itself in reverse order = six fifths is 54.54 divided by 45 =6/5, so 54 is the number.

I’m not sure what sujevtbis this