Each number in the first table represents the points scored by a player on the Ace Academy basketball team. Make a frequency distribution, including relative frequency (percent of total: ) 1 5 8 10 10 13
3 6 9 10 11 13
3 7 9 10 12 14
4 7 10 10 12 14
For the relative frequencies below, round to the nearest tenth.

Score Frequency Relative Frequency
1

%
3

%
4

%
5

%
6

%
7

%
8

%
9

%
10

%
11

%
12

%
13

%
14

%
Total

his chances of getting a coin of higher value is 4/19

step-by-step explanation:

the answer is mp

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)