Two towns tracked the attendance at their summer fairs in 2016 and 2017. The data for each town and year is shown below. Year Ogdenville North Haverbrook 2016 960 500 2017 1008 540 What was the difference between the percent increases for each town from 2016 to 2017?

48 and 5%; 40 and 8%

Step-by-step explanation:

The computation of the difference between the percentage increase for each town from 2016 to 2017 is given below:

Year Ogdenville North Haverbrook

2016              960                500

2017              1008               540

So here the difference would be

For 2016 to 2017

= 1008 - 960

= 48

The percentage increase is

= 48 ÷ 960

= 5%

And,

= 540 - 500

= 40

And, the percentage increase is

= 40 ÷ 500

= 8%

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it