A shopkeeper keeps a record of the number of items he sells. Of the items he sold on a day, 46% were newspapers, 1/4 were pens, 0.12 were chocolates while the remaining were other assorted items. What percent of the items sold were assorted items?

17%

Step-by-step explanation:

The total number would be 100%, or 1. So,

Newspapers + Pens + Chocolates + Assorted Items = 1

46% = 0.46

1 / 4 = 0.25

0.12 = 0.12

So, substitute these numbers into the problem.

0.46 + 0.25 + 0.12 + assorted items = 1

Simplify.

0.83 + assorted items = 1

Subtract 0.83 from both sides.

Assorted items = 0.17, or 17%

So, 17% of the items sold were assorted items.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752