If f(1)= 4 and f(n) = -3f(n-1) then find the value of f(6)

-972

Step-by-step explanation:

if f(1)= 4 and f(n) = -3f(n-1) then find the value of f(6)

If f(1)= 4

f(2) = -3f(2-1)

f(2) = -3f(1)

f(2) = -3(4)

f(2) = -12

f(3) = -3f(3-1)

f(3) = -3f(2)

f(3) = -3(-12)

f(3) = 36

f(4) = -3f(4-1)

f(4) = -3f(3)

f(4) = -3(36)

f(4) = -108

f(5) = -3f(5-1)

f(5) = -3f(4)

f(5) = -3(-108)

f(5) = 324

f(6) = -3f(6-1)

f(6) = -3f(5)

f(6) = -3(324)

f(6) = -972

hence the sixth term of the sequence is -972

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

false

step-by-step explanation:

rulers and compasses arent required in order to bisect an angle because when bisecting angles, you're making a "half circle" and considering in order to bisect an angle it wouldn't be straight, you wouldn't need either of the two