In triangle JKL, sin(b°) = 3/5 and cos(b°) =4/5. If triangle JKL is dilated by a scale factor of 2, what is tan(b°)? a.) tan(b°) = 5/3
b.) tan(b°) = 4/3
c.) tan(b°) = 3/4
d.) tan(b°) = 5/4

C.

Step-by-step explanation:

For right triangles, trigonometric ratios are independent of scale factor, since internal angles do not change. That is:

(1)

If we know that and , then the tangent of the angle b is:

Correct answer is C.

it is C I got it right

Step-by-step explanation:

answer is c

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18