How would you choose to reduce the system shown to a 2 × 2? Explain why you would choose this approach.

hello the system related to your question is missing below is the system

–3x + y – 2z = 10 (1)

5x – 2y – 2z = 12 (2)

x – y + z = 23   (3)

answer :

To reduce the system above to  a 2 * 2 , I would eliminate either Y or Z from the system because a 2 * 2 system requires  X and either Y or Z

Step-by-step explanation:

Given system :

–3x + y – 2z = 10 (1)

5x – 2y – 2z = 12 (2)

x – y + z = 23   (3)

To reduce the system above to  a 2 * 2 , I would eliminate either Y or Z from the system because a 2 * 2 system requires  X and either Y or Z

Eliminating X is not the best way

solving equation 1 and 2

substrate equation (1 ) from equation (2) to eliminate Z

= 8x - 3y = 2

multiply equation (3) by 2 then substrate equation (2) from (3) to eliminate Y

2x - 2y + 2z = 46

-( 5x - 2y - 2z )=  12

= -3x + 4z = 34

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3