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Jennifer starts with a population of 100 amoebas that doubles in size every minute for a number of minutes, m. She writes the expression 100(2") to find the number of amoeba after m minutes. Nathan starts with a population of 10 amoebas that increases 40% in size every minute for a number of minutes, m. He writes the expression (1 + 0.4)" to find the number of amoeba after m minutes. Use the drop-down menus to explain what each part of Jennifer's and Nathan's expressions mean.​
![ansver](/tpl/images/cats/User.png)
![ansver](/tpl/images/cats/User.png)
homozygous. one is homozygous, while two is heterozygous.
![ansver](/tpl/images/cats/User.png)
![ansver](/tpl/images/cats/User.png)
starting with:
5 + x - 12 = 2x - 7
5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)
5 - 12 = x - 7 (combine and cancel x's from both sides)
5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)
0 = x (add numbers together on both sides)
so in order for the equation to be true, x must be 0.
trying x = -0.5
5 + x - 12 = 2x - 7 (original equation)
5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)
5 + -0.5 - 12 = -1 - 7 (did multiplication)
-7.5 = -8 (did addition on both sides)
since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.
trying x = 0
5 + x - 12 = 2x - 7 (original equation)
5 + 0 - 12 = 2(0) - 7 (plug in value of x)
5 + 0 - 12 = 0 - 7 (did multiplication)
-7 = -7 (did addition on both sides)
since -7 equals -7, that demonstrates that the value of 0 for x is correct.
trying x = 1
5 + x - 12 = 2x - 7 (original equation)
5 + 1 - 12 = 2(1) - 7 (plug in value of x)
5 + 1 - 12 = 2 - 7 (did multiplication)
-6 = -5 (did addition on both sides)
since -6 is obviously not equal to -5, the value of 1 for x is wrong.
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