In ΔFGH, the measure of ∠H=90°, the measure of ∠F=24°, and FG = 57 feet. Find the length of HF to the nearest tenth of a foot.

52.1

Step-by-step explanation:

\cos F = \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{x}{57}

cosF=

hypotenuse

adjacent

​

=

57

x

​

\cos 24=\frac{x}{57}

cos24=

57

x

​

57\cos 24=x

57cos24=x

Cross multiply.

x=52.0721\approx \mathbf{52.1}\text{ feet}

x=52.0721≈52.1 feet

the answer is 5636.7

answer is 144

step-by-step explanation: