A ball is thrown into the air with an initial upward velocity of 60 ft/s and its height h in feet after t seconds is given by the function: h= -16t2 + 60t + 6, after how many seconds (to the nearest tenth of a second) will the ball hit the ground?

What kind of question this is what should I do for you

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: