Which of the following pairs of events are mutually exclusive? Rolling a die; A={Rolling an even number}, B={Rolling a number greater than 4} Picking a card; A= {Selecting a 7}, B={Selecting a Heart} Tossing a coin twice; A ={no Heads}, B={at least 1 Head} Rolling two 6-sided dice; A={rolling a sum of 4}, B={rolling a 3 on one die}

Tossing a coin twice; A ={no Heads}, B={at least 1 Head}

Step-by-step explanation:

Mutually exclusive:

If two events are mutually exclusive, if one events happen, the other cannot happen, and vice-versa.

Rolling a die; A={Rolling an even number}, B={Rolling a number greater than 4}

A die has the following outcomes: 1,2,3,4,5,6

Even numbers: 2,4,6

Greater than 4: 5, 6

6 is an outcome of both events A and B, so they are not mutually exclusive.

Picking a card; A= {Selecting a 7}, B={Selecting a Heart}

Cards numbered from 1 to 13, each number with 4 types. So we can have a card of hearts numbered 7, which means that these events are not mutually exclusive.

Tossing a coin twice; A ={no Heads}, B={at least 1 Head}

If you get no heads, the probability of at least 1 head is 0.

If you get at least 1 head, the probability of no heads is 0.

This means that this is the answer, that is, these events are mutually exclusive.

Rolling two 6-sided dice; A={rolling a sum of 4}, B={rolling a 3 on one die}

(3,1) or (1,3) has a sum of 4 and a 3 on one die, which means that these events are not mutually exclusive.

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13

i believe the correct answer is b.