Find the vertexform (x)=x2-12x+36​

Vertex form pf y = x^2 + 12x + 36.

Step-by-step explanation:

y = (x + 6)^2

x-coordinate of vertex:

(x + 6) = 0--> x = - 6

y-coordinate of vertex: y = y(-6) = 36 - 72 + 36 = 0

Vertex form: y = (x + 6)^2

2

Step-by-step explanation:

X=x 2-12x+36

X+X+12x=38

14x=38

X=38/14

X=2

step-by-step explanation:

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d