Two investments totaling $23,500 produce an annual income of $795. One investment yields 2% per year, while the other yields 7% per year. How much is invested at each rate?

$ 6,500 was invested at 7%, while $ 17,000 was invested at 2%.

Step-by-step explanation:

Given that two investments totaling $ 23,500 produce an annual income of $ 795, and one investment yields 2% per year, while the other yields 7% per year, to determine how much is invested at each rate, the following calculation must be performed:

23,500 x 0.07 + 0 x 0.02 = 1,645

11,750 x 0.07 + 11,750 x 0.02 = 1,057.5

5.875 x 0.07 + 17.625 x 0.02 = 763.75

6,500 x 0.07 + 17,000 x 0.02 = 795

Thus, $ 6,500 was invested at 7%, while $ 17,000 was invested at 2%.

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )