Round to the nearest 10th if necessary

Step-by-step explanation:

ah they are getting harder.    :/  they didn't give any angles this time. so figure those out first,   super hero math to the rescue  :P oh and the question is just find angle C  soo.

Angles  C + B + A = 180

we can turn the law of cosines around and use it to find the angle, you are given the formula for that as well in the problem.   it's nice of them to not expect you to memorize the formula   I had to :/   your class is going easy on you.   get out the ruler and smack some students ,  prof. Snape   :D :D  My prof. once threw an eraser at one person b/c they fell asleep in class  :D  when it hit him.. b/c it was all full of chalk.. the eraser.. it kinda  "exploded"   and he woke up coughing...  :o    anyway.. back to math  :P

a= 28

b= 17

c = 15

C = arcCos [ (a^2 + b^2 - c^2)  /  (2 * a * b) ]

C = arcCos[ 28^2 + 17^2 - 15^2  / 2*28 *17 ]

C = arcCos[ 784 + 289 -225 / 952 ]

C = arcCos [ 848 / 952 ]

C = arcCos [0.8907563]

C = 27.03 °

rounded to nearest 10th then is

C = 27.0 °

:)  

btw, does 27 seem right?   to me it does b/c that angle is small

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation:

the answer is 3/2 and for decimal: 1.5

hope i

-lavira: )