A non scale model of the earth has a diameter of 18 in. Within an outer clay layer, there is a core made of a ball with a diameter of 3 in. what is the volume of the clay. Use 3.14 to approximate pi. Round to the nearest hundredth if necessary.​

the formula for the volume of a sphere is

r is the radius, which is half the diameter. Since the diameter of the whole sphere is 18 the radius would be half of that, which is 9. If you plug 9 into the formula you get 3052.08in.cubed. Now you must find the volume of the smaller core, the diameter of the core is 3, so the radius is 1.5 and if you plug that into the formula you get 14.13in.cubed. Since you're finding only the volume of the outside layer, you would subtract the volume of the core from the whole sphere, so 3052.08-14.13=3037.95

Your answer is 3037.95in.cubed

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)