Linear Equations & Linear Systems: Question 10
What is the solution to the following system of equations?

( -3,-1)

Step-by-step explanation:

they are in the same quadrant but both of these points intersect at -3 giving this answer to be -3,-1 can't be zero only because your point in no smack donw on the x-axis.

im sorry if it's wrong just trying to be helpful but i doubt it is.

(-3, -1)

Just look at the point of intersection it falls in (-3, -1)

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

answer: no, but if it does it's a obvious pattern.

step-by-step explanation: