Can you help me with these 2

6. A; 7. D

Step-by-step explanation:

6. 2=5j-28 - Add 28 to both sides

30=5j- Divide by 5 to both sides.

6=j

7. 3/5n +3=18- Subtract by 3 on both sides.

3/5n=15- Multiply by the reciprocal of 3/5 to both sides.

n=25

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation: