Identifying Functions

1) 2

2) -5

3) 0

4) 2/7

5) undefined

6) -4/3

7) 12

Step-by-step explanation:

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1) = 2  

2) =- -5   as workings show -20/4 = -5/1 = -5

3) = undefined  we show equation x = 8

4) = 2/7  

5) = undefined we show equation as y=6

6) = undefined as workings show 12/3 = 4/3 positive

7) = 12   as workings show  24/2  = 12/1

We use the formula  y2-y1  / x2-x1

As we enter a value say - 4  up on y1

or - 4 up on x1

Then it becomes - - (two subtractions together) they become plus =  positive + and either one has a negative sign in front.

if used as second order in bold in formula.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

2,160 π

step-by-step explanation: