Nala can spend no more than $150 per month on gasoline. she has already purchased $60 in gas this month. which inequality can be used to find the maximum number of fill-ups she can purchase during the rest of the month, assuming each fill-up costs $30

a. 30n + 60 ≥ 150
b. 30n + 60 ≤150
c. 60n + 30 ≤ 150
d. 60n + 30 ≥ 150

B.  

Step-by-step explanation:

Given : Nala can spend no more than $150 per month on gasoline.

She has already purchased $60 in gas this month.

The cost of each fill-up = $30

Let x be the number of fill-ups she can purchase during the rest of the month.

Then , the cost of fill-ups she can purchase during the rest of the month = 30x

Then , the inequality can be used to find the maximum number of fill-ups she can purchase during the rest of the month is given by :-

24

step-by-step explanation:

if it takes 8 pounds to make 12 divide 12 by 8 and you get 1.5, 1.5 x 16 = 24

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~