Find the equation of a line that has a slope of -3/2 and passes through the point (2,1) 1. y = -3/2x - 4
2. y = -3/2x + 4
3. y = -3/2x -2
4. y = -3/2x

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4

Step-by-step explanation:

y = -3/2 x + 4

Step-by-step explanation:

y - y1 = m(x - x1)

Here, m = slope = -3/2 & (x1,x2) = (2, 1)

=> y - 1 = (-3/2) (x - 2)

=> y - 1 = -3/2 x + 3

=> y = - 3/2 x + 3 + 1

=> y = -3/2 x + 4

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17