CAN SOMEONE PLEASE HELP ME

Question:

In triangle JKL, the measure of angle L = 90°, KJ = 37, LK = 12, and JL = 35. What ratio represents the cosine of angle J?

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Solution:

The triangle JKL should look like that in the attachment.

Cosine of J = adjacent side/hypotenuse

= LJ/KJ

= 35/37

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

if you need just tell me and i will come to the rescue.

step-by-step explanation: