If a triangle has a leg with a length of 6 units and a hypotenuse with a length of 10 units, find the length of the other leg.

8 units

Step-by-step explanation:

This can be solved using the Pythagorean Theorem:

c² = a² + b²

c is the hypotenuse

a and b are the sides

Solving for the length:

10² = 6² + b²

100 = 36 + b²

b² = 100 - 36

b² = 64

b = √64

b = 8 units

The missing side is 8 units.

i would pic false cause it goes down towards negative

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b