There is a line that includes that point (-6,3)and has a slope of 1/10 . What is its equation in point-slope form?

y = 1/10 x + 18/5

Step-by-step explanation:

The general form of the equation of a line is given as

y = mx + c where m is the slope and c is the intercept

For a line with given points (x1, y1), the equation is given as

y-y1 = m(x-x1)

Hence if there is a line that includes that point (-6,3) and has a slope of 1/10 then the line

y - 3 = 1/10(x --6)

multiply both sides by 10

10y - 30 = x + 6

Rearrange

10y = x + 6 + 30

10y = x + 36

y = 1/10 x + 36/10

y = 1/10 x + 18/5

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.