Please help asap!! (Marking brainliest)
Answer this using a graphing method!

Step-by-step explanation:

5x-2y=10

x-y=-1

Addition method

multiply the second equation by -2 and add it to the first one

5x-2y=10

-2x+2y=2

Total 3x=12

Divide by sides by 3

x=4

Now multiply the second equation by -5 and add it to the first one

5x-2y=10

-5x+5y=5

3y=15

Divide both sides by 3

y=5

Solutions are x=4 and y=5

2nd method

if x-y=-1, so x=y-1

bring the value of x in the first equation

5(y-1)-2y=10

5y-5-2y=10

put the similar term together

3y=15

Divide both sides by 3

y=5

now bring the value of y in one of the equation

x-y=-1

so x-(5)=-1

x=-1+5

x=4

Solutions are x=4; y=5

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.