If pq =r, p,q and r is a real no then show that p and q are both rational no or p and q are irrational no​

Step-by-step explanation:

We are given that

And that r is a real number. This means that r is a decimal, negative number,interger,fraction, or any number except imaginary numbers.

Let say r=6.

We can use two rational numbers to equal six like 2,3

So p and q can be rational numbers.

We can also use two irrational numbers

so

Sqr root of 18 and sqr root of 2 are irrational numbers so p and q can be irrational as well.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.