A ship travels 200 km west from port and then 240 km due south before it is disabled. Illustrate this in a vector diagram. Use trigonometry to find the course that a rescue ship must take from port in order to reach the disabled ship.

Draw an x-y graph with the port at the origin (x=0, y=0) Let up (+y) be north and right (+x) be east. After going west the ship is at (-200, 0), which means x=-200, y=0. Draw the line that it travelled as an arrow from the origin to that point. Then draw another arrow for the next part of its journey, from (-200,0) to (-200,-240)..The course that a rescue ship must take is from (0,0) to (-200,-240)

Step-by-step explanation:

hope it helps

*comment if wrong

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: