A sinusoidal function whose frequency is 3, maximum value is 15, minimum value is -3 has a y-intercept of 6. Which function could be the function described?

a. f(x)=9sin(x/3)+6
b. f(x)=9sin(6pix)+3
c. f(x)=9sin(3x)+3
d. f(x)=9sin(6pix)+6

please explain if you can, if not that’s ok!

A. f(x) = 9sin(x/3) + 6

Step-by-step explanation:

First, we can eliminate B and C because they have the wrong vertical shift.

Since the y intercept is 6, this means the function has a vertical shift up 6 units, represented by a +6 at the end of the equation.

The amplitude is 9, found by calculating the difference between the minimum and maximum values, and dividing it by 2.

(15 - (-3)) / 2

18 / 2

= 9

Using a calculator, find the period given the frequency.

The period (coefficient of x) is 1/3.

So, putting all of these constants together, the correct equation is:

A. f(x) = 9sin(x/3) + 6

A. f(x) = 9sin(x/3) + 6

Step-by-step explanation:

Hope this will help

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2