A square has side lengths of (5x + 6) unitd. An equilateral triangle has side lengths of (7x + 1) units. The square and the triangle have the same perimeter. What is the value of x? Solve algebraically.

x = 3/16

Step-by-step explanation:

Square's perimeter must equal triangle's perimeter.  Using the given formulas for the two different perimeters, we obtain the equation

5x + 6 = 3(7x + 1), where 5x + 7 includes all four sides of the square and

7x + 1 includes all three sides of the triangle.

Performing the indicated multiplication, we get 5x + 6 = 21x + 3.

Combining like terms results in 3 = 16x.

Solving this last equation for x, we get x = 3/16.

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -

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