subject
Mathematics, 22.03.2021 18:00 stacy99

When solving the system of equations 3xβˆ’3y=1 and βˆ’2x+4y=2 algebraically, a good first step is to: A. Multiply 3xβˆ’3y=1 by 2, and multiply βˆ’2x+4y=2 by 3.
B. Multiply 3xβˆ’3y=1 by 3, and multiply βˆ’2x+4y=2 by βˆ’2.
C. Rewrite both equations in slope-intercept form.
D. Add the equations together.

ansver
Answers: 3

Another question on Mathematics

question
Mathematics, 20.06.2019 18:02
Lisa berry plans to rent an apartment for $1,090 per month. she estimates the annual expense will be as shown on the chart below. what is her average monthly cost?
Answers: 3
question
Mathematics, 21.06.2019 21:00
Mr.zimmerman invested $25,000 in an account that draws 1.4 interest, compouneded annually. what is the total value of the account after 15 years
Answers: 1
question
Mathematics, 21.06.2019 21:00
Acomputer store buys a computer system at a cost of $370.80. the selling price was first at $ 618, but then the store advertised a 20 % markdown on the system. answer parts a and b. a. find the current sale price.
Answers: 1
question
Mathematics, 21.06.2019 23:40
Cos^2x+cos^2(120Β°+x)+cos^2(120Β°-x)i need this asap. pls me
Answers: 1
You know the right answer?
When solving the system of equations 3xβˆ’3y=1 and βˆ’2x+4y=2 algebraically, a good first step is to: A...
Questions
question
Mathematics, 23.05.2020 04:57
question
Chemistry, 23.05.2020 04:57
question
History, 23.05.2020 04:57
question
History, 23.05.2020 04:57
question
Business, 23.05.2020 04:57
Questions on the website: 13722360