Jack and Jill are 432 meters apart, but are walking towards each other. Joe walks at a pace of 2 meters per second, while Jill walks at a pace of 3 meters per second. After how many seconds will they meet up?

86.4 seconds.

Step-by-step explanation:

Given that Jack and Jill are 432 meters apart, but are walking towards each other, and Joe walks at a pace of 2 meters per second, while Jill walks at a pace of 3 meters per second, to determine after how many seconds will they meet up, the following calculation must be performed:

432 / (3 + 2) = X

432/5 = X

86.4 = X

So, Jack and Jill will meet after 86.4 seconds.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

i believe that the slope of the line is -5

step-by-step explanation: