Is 7 to the 8th power times 7 equivalent to 7 to the the third power times 7 to third power equivalent?

They are not equivalent.

Step-by-step explanation:

Before we solve the question, we need to know that from the laws of indices:

A^x x A^y = A^(x+y).

7 to the power of 8th power means 7^8

7^8 times 7 means 7^8 x 7. From the laws of indices we have 7^8 x 7 = 7^9.

7 to the power of 3rd power means 7^3

7^3 times 7 to the power of 3rd power means 7^3 x 7^3. From the laws of indices we have 7^3 x 7^3 = 7^6.

Obviously, 7^9 ≠ 7^3 therefore, they are not equivalent.

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!