Important for my exam tomorrow ! Please help

Step-by-step explanation:

Adjacent angles of parallelogram are supplementary.

∠A + ∠D = 180

Divide both sides by 2

∠A + ∠D = 90

∠PAD + ∠ADP = 90       --------------------(I)

IN ΔPAD,

∠PAD + ∠ADP + ∠APD = 180 {angle sum property of triangle}

90  + ∠APD = 180         {from (I)}

          ∠APD = 180 - 90

         ∠APD = 90

∠SPQ = ∠APD             {vertically opposite angles}

∠SPQ = 90°

Similarly, we can prove ∠PQR = 90° ; ∠QRS = 90° and ∠RSP = 90°

In a quadrilateral if each angle is 90°, then it is a rectangle.

PQRS is a rectangle.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

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step-by-step explanation: