Suppose that 18% of employees at a company are vegans. The boss wants to invite 8 random employees to lunch to discuss morale of the company, but she is not sure of the restaurant because of the possibility of vegans being randomly picked. What is the probability of exactly 3 vegans getting chosen for lunch? (using binomialcdf)

The correct answer is addition

The great thing about this problem is they give you everything you need to solve it easily. so the expression is: 12h+30w12h+30wand so everywhere you have an “h” you place 66. and everywhere you have a “w” you place 33. then the expression will look like this: 12(66)+30(33)12(66)+30(33)from here you multiply and then add. getting the following of: $785,862hope this