Please I actually need help please don't answer if you're not good at geometry. show how, please

The inscribed angle theorem says angle ACB has measure equal to half the intercepted arc, so

m∠ACB = 1/2 × 116° = 58°

Triangle ABC is isosceles (since AC and BC are congruent, per the tick mark). This means angles CAB and ABC are both congruent. The sum of the interior angles to any triangle is 180°, so

m∠ACB + m∠ABC + m∠CAB = 180°

58° + 2 m∠ABC = 180°

2 m∠ABC = 122°

m∠ABC = 61°

Applying the inscribed angle theroem again tells you that arcs AC and BC have twice the measure of angle ABC/CAB, so they are both 122°.

The major arc ACB is the sum of arcs AC and BC, so its measure is 2 × 122° = 244°.

To recap:

arc AC = 122°

arc ACB = 244°

m∠ACB = 58°

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

square pyramid

step-by-step explanation:

square prism looks like nothing like that

triangular prism has a rectangular base instead of a square base

tetrahedron has a triangular base