A rectangular garden measures 33 ft by 46 ft. Surrounding (and bordering) the garden is a path 2 ft. Find the area if this other. Be sure to include the correct unit in your answer.

332 ft²

Step-by-step explanation:

A rectangular garden measures 33 ft by 46 ft. Surrounding (and bordering) the garden is a path 2 ft. Find the area of this path. Be sure to include the correct unit in your answer.

Solution:

The area of the rectangular garden = length * breadth = 33 ft. * 46 ft. = 1518 ft²

Since the path surrounding the garden is 2ft, the length of the path with the garden = 46 + 2 + 2 = 50 ft

The width of the path with the garden = 33 + 2 + 2 = 37 ft.

Area of the path with the garden = length * breadth = 50 ft * 37 ft = 1850 ft².

Area of the path = 1850 ft² - 1518 ft.² = 332 ft²

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

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