Which is an equation with a degree of 4, zeros located at (4,0) and (3,0) and a y-intercept located at (0,96)? y=(x+4)(x+3)(x+8)(x+1)

y=(x+4)(x+3)(x−2)(x−1)

y=(x−4)(x−3)(x+2)(x+4)

y=(x−4)(x−3)(x+8)(x−1)

y=(x−4)(x+3)(x+8)(x−1)

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

phosphate, calcium ion, chloride ion, neon atom

step-by-step explanation:

y/x=18

step-by-step explanation:

answer: this is not a question

step-by-step explanation: this is a answer