Jillian lands the beanbag in the hole in about half of her attempts in a beanbag toss game. How can she predict the number of times she will get the beanbag in the hole in her next 5 attempts using a coin toss?

Step-by-step explanation:

So in the case of Jillian, landing the beanbag in the cornhole is 1/2. So this is just like flipping a coin.

the first time she tosses the beanbag she has a 1/2 chance of getting it in the cornhole and 1/2 chance of getting it outside the cornhole. And since she needs to get 5 tosses in a row into the cornhole, we multiply

1/2(1/2)(1/2)(1/2)(1/2)=1/32

I hope that helps :)

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

its very big question plz make it small