A jar contains 6 red jelly beans, 6 green jelly beans, and 6 blue jelly beans. If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be green and the second will be green as well?

the probability is 5 ÷ 51

Step-by-step explanation:

The computation of the probability is shown below:

 = green jelly beans ÷ total jelly beans × remaining jelly beans ÷ remaining total jelly beans

=  6 ÷ 18 × 5 ÷ 17

= 30 ÷ 306

= 5 ÷ 51

Hence, the probability is 5 ÷ 51

answer: 298143

step-by-step explanation:

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1