Write the equation in standard form for the circle x^2 + y^2 - 14y + 24 = 0

x^2+(y-7)^2=25

Step-by-step explanation:

x^2+y^2-14y=-24

x^2+(y-7)^2-49=-24

x^2+(y-7)^2=25

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94