A new car is purchased for 20000 dollars. The value of the car depreciates at 11% per year. To the nearest tenth of a year, how long will it be until the value of the car is 5700 dollars?

0.285

Step-by-step explanation:

first we will have to find our equation:

20,000(p = principal) x r (rate) = 5,700

20,000 × (r) = 5,700

since we are multiplying, we would divide the equation:

5,700 / 20,000

this would then equal to our answer 0.285

to check your answer we can do,

0.285 x 20,000

which would give use our depreciated value of $5,700.

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m