A school of fish has the population of 200. The population is decreasing at a rate of 5% a year how can you write in exponential decay function to find the quarterly decay rate

Step-by-step explanation:

Initial population of fish = 200

Decay rate by which population is decreasing = 5% per year

Number of quarters in a year = 4

Rate of decay in a quarter = = 1.25%

Formula for the exponential decay in the population is,

Here, P = Final population

P₀ = Initial population

r = Rate of decay per quarter

n = Number of quarters for the total decay

By substituting these values in the formula,

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

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