Which expression is equivalent to 98x8y5z40 in the lowest term​

Regents Exam Questions A.A.16: Rational Expressions 1 Name:

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1

A.A.16: Rational Expressions 1: Simplify fractions with polynomials in the numerator and

denominator by factoring both and renaming them to lowest terms

1 The expression 9x 4  27x

6

3x 3 is equivalent to

1) 3x(1  3x)

2) 3x(1  3x 2

)

3) 3x(1  9x 5

)

4) 9x

3

(1  x)

2 Which expression represents 2x 2  12x

x  6 in simplest

form?

1) 0

2) 2x

3) 4x

4) 2x  2

3 Which expression is in simplest form?

1) x

x 2

2) 9

x 2  9

3) x 2  4

x  2

4) x 2  6x  9

x 2  x  6

4 Which expression represents x 2  2x  15

x 2  3x

in

simplest form?

1) 5

2) x  5

x

3) 2x  5

x

4) 2x  15

3x

5 For all values of x for which the expression is

defined, 2x  x 2

x 2  5x  6 is equivalent to

1) 1

x  3

2) x

x  3

3) 1

x  2

4) x

x  2

6 Which expression represents 25x  125

x 2  25 in simplest

form?

1) 5

x

2) 5

x

3) 25

x  5

4) 25

x  5

Regents Exam Questions A.A.16: Rational Expressions 1 Name:

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2

7 Which expression represents x 2  x  6

x 2  5x  6

in

simplest form?

1) x  2

x  2

2) x  6

5x  6

3) 1

5

4) 1

8 Express x 2  3x  10

x 2  5x

as a fraction in simplest form.

9 Express in simplest form: x 2  5x  24

x 2  8x

10 Simplify: x 2  6x  5

x 2  25

11 Simplify:

9x 2  15xy

9x 2  25y 2

12 The area of a rectangle is represented by

x 2  5x  24. If the width of the rectangle is

represented by x  8, express the length of the

rectangle as a binomial.

ID: A

1

A.A.16: Rational Expressions 1: Simplify fractions with polynomials in the numerator and

denominator by factoring both and renaming them to lowest terms

Answer Section

1 ANS: 2

9x 4  27x

6

3x 3  9x 4

(1  3x 2

)

3x 3  3x(1  3x 2

)

REF: fall0718ia

2 ANS: 2

2x 2  12x

x  6  2x(x  6)

x  6  2x

REF: 060824ia

3 ANS: 2

. .

REF: 060712b

4 ANS: 2

x 2  2x  15

x 2  3x  (x  5)(x  3)

x(x  3)  x  5

x

REF: 060921ia

5 ANS: 2

REF: 060202b

6 ANS: 4

25x  125

x 2  25  25(x  5)

(x  5)(x  5)  25

x  5

REF: 080821ia

7 ANS: 1

x 2  x  6

x 2  5x  6  (x  3)(x  2)

(x  3)(x  2)  x  2

x  2

REF: 011130ia

8 ANS:

x  2

x

REF: 088704siii

ID: A

2

9 ANS:

x  3

x . x 2  5x  24

x 2  8x  (x  8)(x  3)

x(x  8)  x  3

x

REF: 060837a

10 ANS:

x  1

x  5 .

REF: 010631a

11 ANS:

3x

3x  5y

REF: 069924a

12 ANS:

x 2  5x  24

x  8  (x  8)(x  3)

x  8  x  3

REF: 061131ia

Step-by-step explanation:

To write a rational expression in lowest terms, we must first find all common factors (constants, variables, or polynomials) or the numerator and the denominator. Thus, we must factor the numerator and the denominator. Once the numerator and the denominator have been factored, cross out any common factors.

cross out any comen facters

Step-by-step explanation:

answer: b.36 feet

step-by-step explanation: