During a building project, a brick is dropped from a height of 1,936 ft. If the
equation for height as a function of time is
h(t) = -16t2 + initial height where t is time
in seconds and h(t) is height in feet, how
many seconds will it take for the brick to
hit the ground?
[?] seconds

11 seconds

Step-by-step explanation:

h(t) = -16t^2 + 1936

When  the brick hits the ground h = 0 so:

-16t^2 + 1936 = 0

-16t^2 = -1936

t^2 = -1936/-16

= 121

t = 11 seconds.

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi