A point is in Quadrant 3 and on the unit circle. If its x-coordinate is -4/5, what is the y-coordinate of the point?

The y-coordinate of the point is -3/5

Step-by-step explanation:

Here, we want to get the y-coordinate of the point

when we talk of the unit circle, we mean a circle that has its radius equal to just 1 unit

Now, on the third quadrant, we have the x axis value as negative, and also the y axis value as negative

In the unit circle, the Pythagoras’ theorem works for all quadrants; with the radius representing the hypotenuse of the right triangle, the x and y coordinates value represents the other sides of the triangle

Mathematically, from the theorem;

the square of the hypotenuse (radius of the unit circle) equals the sum of the squares of the two other sides

Thus, we have it that;

1^2 = (-4/5)^2 + y^2

1 = 16/25 + y^2

y^2 = 1 - 16/25

y^2 = 9/25

y = √(9/25)

y = +3/5 or -3/5

But since the y-coordinate value is supposed to be negative, we have to choose y = -3/5 as our answer (for the third quadrant)

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol