On a certain hot summer day, 673 people used the public swimming pool. The daily prices are 1.75 for children and 2.00 for adults. The receipts for admission totaled to $1249.50. How many children and how many adults swam at the public pool that day?

120 children and 388 adults bought tickets for the swimming pool

Explanation:

Create two simultanous equations:

Let c stand for the number of children that bought a ticket, and a stand for the number of adults that bought a ticket, you get your first equation, being

c

+

a

=

508

then, you now create a second equation for the prices of the tickets.

(price of childrens tickets)(number of children that swam)+(price of adults tickets)(number of adults that swam) = total money collected

so:

1.75

c

+

2.25

a

=

1083.00

now we still know, that

a

=

508

−

c

so we can substitute it into the second formula

1.75

c

+

2.25

(

508

−

c

)

=

1083

now its just simple algebra

1.75

c

+

1143

−

2.25

c

=

1083

60

=

0.5

c

so:

c

=

120

now we know, that 120 children went to the swimming pool.

and we still have the formula from before:

a

=

508

−

c

so

a

=

388

4th option is correct xy=-10

if this was to u plzz mark me the brainliest

step-by-step explanation: