Solve by elimination: 3x + 4y = 0
5x-3y = -58
A (6, -8)
B (-6, -8)
C (-8, 6)
D ( 8, 6)

x=−8

y=6=

Step-by-step explanation:

3x+4y=0

5x−3y=−58

In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

3x+4y=0,5x−3y=−58

To make 3x and 5x equal, multiply all terms on each side of the first equation by 5 and all terms on each side of the second by 3.

5×3x+5×4y=0,3×5x+3(−3)y=3(−58)

Simplify.

15x+20y=0,15x−9y=−174

Subtract 15x−9y=−174 from 15x+20y=0 by subtracting like terms on each side of the equal sign.

15x−15x+20y+9y=174

Add 15x to −15x. Terms 15x and −15x cancel out, leaving an equation with only one variable that can be solved.

20y+9y=174

Add 20y to 9y.

29y=174

Divide both sides by 29.

y=6

Substitute 6 for y in 5x−3y=−58. Because the resulting equation contains only one variable, you can solve for x directly.

5x−3×6=−58

Multiply −3 times 6.

5x−18=−58

Add 18 to both sides of the equation.

5x=−40

Divide both sides by 5.

x=−8

The system is now solved.

x=−8,y=6

Coordinates are: (-8,6)

Graph:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

24/56=hx^7

step-by-step explanation: