What are the missing numbers?

You can use the formula 500 * 1.03^x to solve for any year.

year 4 is 500 * 1.03^(4) = 562.75

year 6 is 500 * 1.03^(6) = 597.03

Year 7 is 500 * 1.03^(7) = 614.94

Step-by-step explanation:

The amount is increasing, and there are two main ways for that to happen.  Addition and multiplication.  So let's see if it keeps getting the same amount added or multiplied.  

0 to 1 goes from 500 to 515, so 15 is added.  but 15.45 is added from 1 to 2, so we can't just do simple addition.

using multiplication 0 to 1 has 1.03 multiplied.  if you multiply by it again you do get 530.45, so we have established what is happening.  

You can use the formula 500 * 1.03^x to solve for any year.

so year 4 is 500 * 1.03^(4) = 562.75

year 6 is 500 * 1.03^(6) = 597.03

Year 7 is 500 * 1.03^(7) = 614.94

entering that problem on the tube might get you an answer

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents