Find the numerical value of the log expression. \log a=-10\hspace{15px} \log b=-10\hspace{15px} \log c=12
loga=−10logb=−10logc=12
\log \frac{c^2}{a^6b^7}
log
a
6
b
7

c
2

​ ​

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.